Proposition 52: Statements entailing their own negation (inference rule)
Given that \phi entails its negation \neg \phi , we may infer that \neg \phi holds: \cfrac{\phi \vdash \neg \phi}{\vdash \neg \phi}.
Proof: By the identity rule, \phi entails \phi . Then, by negation introduction, we infer \neg \phi holds. \square