Proposition 99: Reverse of conditional introduction (inference rule)
Given that the implication \phi \Rightarrow \psi holds, we may infer that \phi entails \psi : \cfrac{ \vdash (\phi \Rightarrow \psi)}{\phi \vdash \psi}.
Proof: Assume \phi . By conditional elimination, we infer that \psi holds. Thus, \phi entails \psi . \square