Proposition 62: Double negation elimination for entailment (rule)
Given that the double negation \neg \neg \phi entails \neg \neg \psi , we may infer \phi entails \psi : \cfrac{\neg \neg \phi \vdash \neg \neg \psi}{\phi \vdash \psi}.
Proof: Assume \phi . By double negation introduction, \neg \neg \phi holds. By the cut rule, this means \neg \neg \psi holds. We then get by double negation elimination that \psi holds, meaning we have showed \phi entails \psi . \square